“Simplify” all of these expressions: rewrite them in a tidier form without parenthesis, and with a minimal number of terms/characters. You can check your answer by testing the initial expression and your result at some simple values of the variables to ensure they’re equal.
\(\displaystyle -(x-5) \)
\(\displaystyle (11x-8)+5 \)
\(\displaystyle 7-(3x-4) \)
\(\displaystyle (7m-1)-(5+4m) \)
\(\displaystyle 9-4(12t-8) \)
\(\displaystyle -\tfrac{1}{2}(4x-7) \)
\(\displaystyle (7x+22)3 \)
\(\displaystyle x(17-y) \)
\(\displaystyle (x+8)^2 \)
\(\displaystyle (x-1)(x+4) \)
\(\displaystyle (2-x)(x+9) \)
\(\displaystyle (2x-15)(5x+9) \)
\(\displaystyle (7-2t)^2 \)
\(\displaystyle (7-2t)^3 \)
\(\displaystyle \bigl(1-\tfrac{1}{2}x\bigr)(x+8) \)
\(\displaystyle \bigl(x^2+x\bigr)(3+x) \)
\(\displaystyle (t-u)(x-7) \)
\(\displaystyle (x+y+z)(3+t) \)
\(\displaystyle (11-3m)(m-7k) \)
\(\displaystyle (1+x+y)(7-t) \)
\(\displaystyle \bigl(3t-(2+5t)\bigr)+1 \)
\(\displaystyle k-2\bigl(2(3-k)+6k\bigr) \)
\(\displaystyle x\Bigl(x+\bigl(x(x-4)-3\bigr)2\Bigr)-1 \)
\(\displaystyle \frac{(4x-18)}{3} \)
\(\displaystyle \frac{8-(t+12)}{2} \)
\(\displaystyle \frac{5(x-1)+2(10-3x)}{5} \)
\(\displaystyle \frac{3}{(3x-1)(x+1)} \)