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Consider the differential equation
\(\dot{y} = t^2 + 2\cos(t)\).
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What is the general solution
to this differential equation?
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What is the particular solution \(y = f(t)\)
to this differential equation
corresponding to the initial condition
\[f\left(\frac{\pi}{2}\right) = \frac{\pi^3}{24}\,?\]
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An adult is riding their tricycle along
the straight road that passes by their house.
Their velocity \(\dot y\) (mph) can be modelled by
the differential equation \({\dot{y} = t^2 + 2\cos(t)}\)
as a function of \(t\) hours since they left their house.
If the tricyclist was \(\frac{\pi^3}{24}\) miles from their house
\(\frac{\pi}{2}\) hours after they left,
how far will the tricyclist be from their home in \(2\pi\) hours?
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Consider the differential equation
\( \ddot{y} +t(4+3t) = 2+2\dot{y}+3y\,. \)
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Show that \(y = t^2 + \mathrm{e}^{3t}\)
is a particular solution.
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Show that \(y = t^2 - 7\mathrm{e}^{-t}\)
is also a particular solution.
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Show that
\(y = t^2 + C_1\mathrm{e}^{-t} + C_2\mathrm{e}^{3t}\)
is the general solution.
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What is the particular solution \(y = f(t)\)
to this differential equation
corresponding to initial conditions
\(f(0) = -30\) and \({f(\ln(2)) = \big(\!\ln(2)\big)^2\,?}\)
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Show that the logistic curve
\[ y = \frac{M}{1+C_1\mathrm{e}^{-kMt}} \]
with parameters \(M\) and \(k\)
is the general solution to the differential equation
\({\dot{y} = k\left(\!M-y\right)y\,.}\)