For two vectors
    \(\bm{u} =\langle u_1,u_2,u_3 \rangle\) and \(\bm{v} = \langle v_1,v_2,v_3 \rangle,\)
    their cross-product \(\bm{u}\times\bm{v}\)
    is the vector computed as 
    \[
    \begin{align*}
    \bm{u}\times\bm{v} 
    = \operatorname{det}\!\begin{pmatrix}
    \mathbf{i} & \mathbf{j} & \mathbf{k}
    \\ u_1 & u_2 & u_3
    \\ v_1 & v_2 & v_3
    \end{pmatrix}
    &= \operatorname{det}\!\begin{pmatrix}u_2 & u_3 \\ v_2 & v_3\end{pmatrix}\mathbf{i}
    - \operatorname{det}\!\begin{pmatrix}u_1 & u_3 \\ v_1 & v_3\end{pmatrix}\mathbf{j}
    + \operatorname{det}\!\begin{pmatrix}u_1 & u_2 \\ v_1 & v_2\end{pmatrix}\mathbf{k}
    \\&= \Bigl\langle\big(u_2v_3\!-\!u_3v_2\big),
    -\big(u_1v_3\!-\!u_3v_1\big),
    \big(u_1v_2\!-\!u_2v_1\big)\Bigr\rangle\,.
    \end{align*}
    \]
    Generically the resulting vector will be orthogonal to both \(\bm{u}\) and \(\bm{v}\)
    and will point in the direction indicated by the right-hand rule.
    Its length will be proportional to the sine of the angle between \(\bm{u}\) and \(\bm{v}.\)
    Specifically, the magnitude of the cross product will be 
    the product of the vectors’ individual magnitudes 
    weighted by the sine of the angle between them:
    \(|\bm{u} \times \bm{v}| = |\bm{u}||\bm{v}|\sin(\theta).\)
    Not coincidentally, this number also equals the area of the parallelogram 
    (twice the area of the triangle) framed by \(\bm{u}\) and \(\bm{v}\).
    As a special case, two vectors \(\bm{u}\) and \(\bm{v}\) are parallel
    if and only if \(\bm{u} \times \bm{v} = \bm{0}.\)
    
    Given a plane in three-dimensional space
    a vector \(\bm{n}\) is normal to the plane
    if it is orthogonal to every vector parallel to the plane;
    i.e. \(\bm{n}\cdot\bm{v}=0\) 
    for every vector \(\bm{v}\) parallel to the plane.
    Three non-colinear points in space uniquely determine a plane.
    Given three such points \(P\) and \(Q\) and \(R\)
    we can calculate a vector normal to that plane as 
    \(\overrightarrow{PQ}\times\overrightarrow{PR}.\)
The scalar triple product of vectors \(\bm{u}\) and \(\bm{v}\) and \(\bm{w}\) is calculated as \(\bm{u} \cdot \bigl(\bm{v} \times \bm{w}\bigr)\) and gives the volume of the parallelepiped, the three-dimensional analog of a parallelogram, (and six times the volume of the tetrahedron) framed by those three vectors. Specifically, the vectors \(\bm{u}\) and \(\bm{v}\) and \(\bm{w}\) all lie in the same plane (are coplanar) if and only if \(\bm{u}\cdot\bigl(\bm{v}\times\bm{w}\bigr)=0.\)